PHP Regex – Issue with forward slashes and alternation

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I have a series of URLs like so: 

http://www.somesite.com/de/page
http://www.somesite.com/de/another
http://www.somesite.com/de/page/something
http://www.somesite.com/de/page/bar

I need to search the block of text and pull the language and am using a regex like so:

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/(de|en|jp)/

I’m trying to find and replace, via preg_replace and including the forward slashes: 

/de/
/en/
/jp/

However, this doesn’t work and does not include the slashes. I’ve tried escaping the slashes with , \. I’ve tried placing the needle in preg_quote but this breaks the alternation.

I feel like I am missing something very simple here!

edit:

Full function call: 

preg_replace("/(de|en|jp)/", "/".$newLang."/", $url);

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(tagged magento and wordpress as I am trying to solve an issue with unifying the navigation menu when both CMSes are multilingual)

Post Views: 3

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2 comments

  1. You don’t have to use slashes as delimiters, but you have to have some delimiter. Try this:

    if( preg_match("(/(de|en|jp)/)",$url,$m)) {
    $lanuage = $m[1];
}

  2. You can use a different delimiter, such as %.

    if (preg_match('%/(de|en|jp)/%', $url, $match)) {
    $lang = $match[1];
}

    That should help you, just modify what you have :).