How can I find the ‘public absolute’ path of a file?

Short Version

I need to give in the absolute path of a Javascript file that is to be hooked into something. It works if I hardcode it into

Read More

‘http://mywebsite.com/folder/script.js’

However I prefer not to hardcode it in. I can do dirname(___FILE___), which gives me this:

‘/home/public_html/folder/script.js’

But that fails, the script isn’t loaded. What’s the best practice to find the absolute path (starting with ‘http://’)?

Long Version

On this page in the WordPress documentation relating to the tinyMCE plugin creation, I found this:

// Load the TinyMCE plugin : editor_plugin.js (wp2.5)
function add_myplugin_tinymce_plugin($plugin_array) {
   $plugin_array['myplugin'] = URLPATH.'tinymce/editor_plugin.js';
   return $plugin_array;
}

There’s a note at the bottom saying:

Note: when using the mce_external_plugins filter, the url should point
to the actual plugin file, as in the example above.

A bit higher in the documentation they say

mce_external_plugins: passes in/out an associative php array
‘plugin_name’ => ‘plugin_url’. The url should be absolute and on the
same domain as your WordPress installation.

I am completely puzzled because I can’t find any information about ‘URLPATH’ which is used in their example. I don’t think it exists in PHP, WP or TinyMCE, but I could be wrong.

Incidentally, were this to be an error in the WP documentation, what would I replace URLPATH with to make it work?

Related posts

Leave a Reply

1 comment

  1. Assuming your resource is included in your Plugin:

    • plugins_url() is the URL to wp-contentplugins (Codex ref)

    So if you have a .js file in wp-contentpluginsplugin-slugfile.js:

    <?php echo plugins_url() . 'plugin-slugfile.js'; ?>

    BUT WAIT!!

    If your purpose is actually to load a javascript file, you actually want to enqueue that file, using wp_enqueue_script(), hooked into the wp_enqueue_scripts hook.

    And wp_enqueue_script() uses the filepath rather than the URL, so you could use dirname(___FILE___) if that’ what you’re comfortable with.