I found some similar questions with good answers but i couldnt figure out how to apply this to my specific case. I have a site where users can rate there favorite post from 1-6. Every number is a different category.
Now i need to know the most frequently votes for every single post. So i need to count every post id and than the most frequent values of every post id.
After that i wanna update every result in another table. (dont know how to figure this out right now i’m not that good with Mysql yet).
this are the two columns where i need to know how often every post exist in post_id and what is the most frequently voting number of every single post.
just an example of my table (value = voting)
value | post_id
---------------
3 | 12
1 | 6
4 | 13
2 | 5
6 | 12
5 | 6
i need the output like this to know which post is mostly votet for which category.
post | most voted in this category
---------------
1 | 3
2 | 5
3 | 6
4 | 1
5 | 4
6 | 6
i need this for every post in the table. and than i would need to update every post in another table. i guess i have to do this in a loop.
but im already stuck at the first part.
all i have is this. for the first part.
<?php global $wpdb;
$test = $wpdb->get_results('SELECT posts_id, value, COUNT(posts_id) AS ActionCount
FROM rating_item_entry_value
GROUP BY posts_id
ORDER BY ActionCount DESC');
echo '<pre>';
print_r($test);
echo '</pre>';
and this is the output i get
Array
(
[0] => stdClass Object
(
[posts_id] => 0
[value] => 5
[ActionCount] => 7
)
[1] => stdClass Object
(
[posts_id] => 221
[value] => 3
[ActionCount] => 3
)
[2] => stdClass Object
(
[posts_id] => 197
[value] => 5
[ActionCount] => 2
)
[3] => stdClass Object
(
[posts_id] => 164
[value] => 3
[ActionCount] => 1
)
)
for the example.
I have no idea how to do this better, trying a lot but can’t figure it out. does anyone has a good solution how to get the most frequent number for every single id? (and maybe how to safe the results in a variable to update every post in another table within a loop?) thank u so much for any help. regards
most frequently means count aggregation and group by frequency. you can map this to your problem:
// edit to you mean that